This is an AS level Biology question I am needing some help with - please explain your answer to help me!
it says: Ribonuclease is an enzyme. It is 127 amino acids long. What is the minimum number of DNA bases needed to code for ribonuclease?What is the minimum number of DNA bases needed to code for ribonuclease?
So for every amino acid there are codons that code for them. The codon is made up of 3 nucleic acids such as AUG, GUA. (adenine, uracil, guanine). When the mRNA is translated, 3 bases are used to make 1 amino acid. RNA is made from transcription from a DNA template. For every 1 DNA base you get 1 RNA base to pair with it. So therefore, the number of DNA bases for a 127 amino acid peptide would be 127 x 3 = 381 DNA bases.
Hope this helpsWhat is the minimum number of DNA bases needed to code for ribonuclease?
jon is partially right, but you'll also need a stop codon so +3 to his number
there is also the UTR and promotor but you probably don't need to know that yet and hypothetically not needed for a minimum
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